5.9.1. Exercises: Overloading on const
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5.9.1. Exercises: Overloading on const

  1. In Example 5.18, the compiler can tell the difference between calls to the const and to the non-const versions of operator[] based on the const-ness of the object.

    Example 5.18. src/const/overload/constoverload-client.cpp

    #include "constoverload.h"
#include <iostream>

int main( ) {
    using namespace std;
    Point3 pt1(1.2, 3.4, 5.6);
    const Point3 pt2(7.8, 9.1, 6.4);
    double d ;
    d = pt2[2];    1
    cout << d << endl;
    d = pt1[0];    2
    cout << d << endl;
    d = pt1[3];    3
    cout << d << endl;
    pt1[2] = 8.7;  4
    cout << pt1 << endl;
    //  pt2[2] = 'd';
    cout << pt2 << endl;
    return 0;
}

    1

    __________

    2

    __________

    3

    __________

    4

    __________

    Which operator is called for each of the notes?

  2. Why is the last assignment commented out?

[ fromfile: constoverloading.xml id: None ]

Generated: 2012-03-02 © 2012 Alan Ezust and Paul Ezust.
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